By additivity of limits, the same holds for an arbitrary simple function. That is, for any function of the form:
We have that:
Finally, let be arbitrary.
Let be fixed.
Since the simple functions are dense in , there exists a simple function such that:
By our previous argument and the definition of a limit of a complex function, there exists such that for all :
By additivity of integrals:
For all , the right side is bounded by by our previous arguments. Since was arbitrary, this establishes:
for all .
The Riemann–Lebesgue lemma holds in a variety of other situations.
- If ƒ is L1 integrable and supported on (0, ∞), then the Riemann–Lebesgue lemma also holds for the Laplace transform of ƒ. That is,
- as |z| → ∞ within the half-plane Re(z) ≥ 0.
- A version holds for Fourier series as well: if ƒ is an integrable function on an interval, then the Fourier coefficients of ƒ tend to 0 as n → ±∞,
- This follows by extending ƒ by zero outside the interval, and then applying the version of the lemma on the entire real line.
- A similar statement is trivial for L2 functions. To see this, note that the Fourier transform takes L2 to L2 and such functions have l2 Fourier series.
- However, the lemma does not hold for arbitrary distributions. For example, the Dirac delta function distribution formally has a finite integral over the real line, but its Fourier transform is a constant (the exact value depends on the form of the transform used) and does not vanish at infinity.
The Riemann–Lebesgue lemma can be used to prove the validity of asymptotic approximations for integrals. Rigorous treatments of the method of steepest descent and the method of stationary phase, amongst others, are based on the Riemann–Lebesgue lemma.
If ƒ is an arbitrary integrable function, it may be approximated in the L1 norm by a compactly supported smooth function g. Pick such a g so that ||ƒ − g||L1 < ε. Then
and since this holds for any ε > 0, the theorem follows.