What type of conic section is the following equation?
5x2 - y = 12
parabola
circle
hyperbola
ellipse

The conic section for the equation 5x^2 - y = 12 is parabola.

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Question

Asked 9/18/2012 9:15:05 AM

Updated 7/11/2014 9:04:52 AM

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The conic section for the equation 5x^2 - y = 12 is parabola.

Added 7/11/2014 9:04:52 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [7/11/2014 9:11:55 AM]

Locate the gerund (not the gerund phrase) and identify its use.
I always enjoy eating a midnight snack.
Gerund:
Noun Use: **Weegy:**
I always enjoy eating a midnight snack.
Gerund: eating
Noun Use: direct object
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Not Answered

Updated 11/15/2015 8:51:27 AM

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What type of conic section is the following equation?
16x2 - 300 - 25y2 = 100
parabola
circle
hyperbola
ellipse **Weegy:** The answer is Circle. (More)

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Expert Answered

Updated 7/11/2014 8:58:01 AM

1 Answer/Comment

Roman numerals in an outline signify main ideas.
True
False **Weegy:** Roman numerals in an outline signify main ideas. TRUE. (More)

Question

Updated 5/31/2016 12:24:18 AM

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What type of conic section is the following equation?
9x2 + 4y2 - 36 = 0
parabola
circle
hyperbola
ellipse

Question

Updated 7/11/2014 8:53:54 AM

1 Answer/Comment

What type of conic section is the following equation?
4x2 + 4(y2 - 4) = 0
parabola
circle
hyperbola
ellipse

Question

Updated 7/11/2014 9:00:16 AM

1 Answer/Comment

The conic section for the equation 4x^2 + 4(y^2 - 4) = 0 is circle.

4x^2 + 4(y^2 - 4) = 0

4x^2 + 4y^2 - 16 = 0

4x^2 + 4y^2 = 16

x^2 + y^2 = 4 which is the equation for a circle with center (0, 0) and radius 2.

4x^2 + 4(y^2 - 4) = 0

4x^2 + 4y^2 - 16 = 0

4x^2 + 4y^2 = 16

x^2 + y^2 = 4 which is the equation for a circle with center (0, 0) and radius 2.

Added 7/11/2014 9:00:16 AM

This answer has been confirmed as correct and helpful.

Confirmed by jeifunk [7/11/2014 9:02:18 AM]

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